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Iodine can be prepared by the following ...

Iodine can be prepared by the following reactions.
`2NaIO_(3) + 5NaSO_(3) rarr 2NaSO_(4) + 2Na_(2) SO_(4) + H_(2)O + I_(2)`
How much `NaHSO_(3)` is required to produce `381 g` of `I_(2)`?

A

`156.0 g`

B

`390.0 g`

C

`520.0 g`

D

`780.0 g

Text Solution

Verified by Experts

The correct Answer is:
D
Mol of `I_(2) = (381)/(254) = 1.5 "mol" I_(2)`
`(1.5 "mol" I_(2)) ((5 "mol" NaHSO_(3))/("mol" I_(2))) ((104 g NaHSO_(3))/("mol" NaHSO_(3)))`
`implies 1.5 xx 5 xx 104 = 780 g "of" NaHSO_(3)`
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