Salt cake `(Na_(2)SO_(4))` is prepared as follows:
`2NaCl + H_(2) SO_(4) rarr Na_(2)SO_(4) + 2HCl`
How much salt cake could be produced from `100.0 g` of 90% pure saltin the above reaction?

Options

A. `109.8 g`
B. `54.9 g`
C. `36.6 g`
D. `209.8 g`

Answer

A

Explanation

Weight of `Na_(2)SO_(4) = (100 g NaCl)`
`((90.0 g NaCl)/(100 g "mixture"))((1 "mol" NaCl)/(58.5 g NaCl))`
`((1 "mol" Na_(2)SO_(4))/(2 "mol"NaCl))((142 g NaSO_(4))/("mol"Na_(2)SO_(4)))`
`= (100 xx 90 xx 1 x 1 x 142)/(100 xx 58.5 xx 2)`
`= 109.79 ~~ 109.8 g`