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A bulb contains 1.6 g of O(2) contains....

A bulb contains `1.6 g` of `O_(2)` contains.

A

0.05 mol of `O_(2)`

B

`3.011 xx 10^(22)` molecules of `O_(2)`

C

`1.12 L` of `O_(2)` at `STP`

D

`1.22 L` of `O_(2)` at `STP`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
a. Moles of `O_(2) = (1.6)/(32) = 0.05`
b. Molecules of `O_(2) = 0.05 xx 6.023 xx 10^(23) = 3.011 xx 10^(22)`
d. Volume of `O_(2)` at `STP = 0.05 xx 22.4 = 1.12 L`
d. `V_(O_(2))` at `SATP = 0.05 xx 24.4 = 1.22 L`
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