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If 0.5 g of a mixture of two metals. A a...

If `0.5 g` of a mixture of two metals. `A` and `B` with respective equivalent weights 12 and 9 displace `560 mL` of `H_(2)` at `STP` from an acid, the composition of the mixture is

A

`40% A, 60% B`

B

`60% A, 40% B`

C

`30% A, 70% B`

D

`70% A, 30% B`

Text Solution

Verified by Experts

The correct Answer is:
A
1 mol of `H_(2) = 22400 mL = 2 Eq "of" H_(2)`
`1 Eq of H_(2) = 11200 mL`
Eq of `H_(2) = (560)/(11200) = (1)/(20) Eq`
[Let of weight of `A` be weight of `B = 0.5 - x`
Eq of `A + Eq "of" B = Eq "of" H_(2)`
`(x)/(12) + (0.5)/(9) = (1)/(20)`
% of `A = (0.2 xx 100)/(0.5) = 40%`
% of `B = 60%`
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