Home
Class 11
CHEMISTRY
A bag contains 0.32 g of oxygen. The sam...

A bag contains `0.32 g` of oxygen. The same valume of an unknown gas `A` under similar conditions of temperature and pressure weigh `0.26 g`. The gas `A` is known to contain only `C` and `H` in 1:1 ratio. The molecular formula of the compound is

A

`C_(2)H_(2)`

B

`C_(4)H_(4)`

C

`C_(3)H_(4)`

D

`CH`

Text Solution

Verified by Experts

The correct Answer is:
A

Moles of `O_(2)` in bag `A = 0.32//32 = 0.01` mol
Same volume of unknown gas = 0.01 mol
0.01 mol of unknown gas `A = 0.26 g`
mol of unknown `A = (0.26)/(0.01) = 26 g`
`Mw` of unknown gas `A = 26 g`
Empirical formula `= CH`
Empirical formula weight `= 12 + 1 = 13g`
`n = ("Molecular formula weight")/("Empirical formula weight") = (26)/(13) = 2`
Molecular formula `= (CH)_(2) = C_(2) H_(2)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

One litre of an unknown gas weighs 1.25 g at NTP. The possible formula of the gas is :

The empirical formula of a non - electrolyte is CH_(2)O . A solution containing 6 g of the compound exerts the same osmotic pressure as that 0.05 M glucose solution at the same temperature. The molecular formula of the compound is

0.30g of an organic compound contaiining C, H and Oxygen an combustion yields 0.44g CO_2 and 0.18g H_2O . If one mol of compound weight 60, then molecular formula of the compound is

At same temperature and pressure, the rate of diffusion of hydrogen gas is 3 sqrt( 3) times that of a hydrocarbon having molecular formula, C_(n) H_(2n-2) .The value of n is

0.30g of an organic compound containing C , H and Oxygen on combustion yields 0.44g CO_(2) and 0.18g H_(2)O . If one mole of compound weighs 60 , then molecular formula of the compound is