Home
Class 11
CHEMISTRY
5.6 g of a metal forms 12.7 g of metal c...

`5.6 g` of a metal forms `12.7 g` of metal chloride. Hence equivalent weight of the metal is

A

127

B

254

C

56

D

25

Text Solution

Verified by Experts

The correct Answer is:
D

Weight of `Cl` reacted `= 12.7 - 5.6 - 7.1 g`
`7.1 g Cl -= 5.6` of metal
`35.5 g Cl = 28 g` of metal
Promotional Banner

Similar Questions

Explore conceptually related problems

1.0 g of metal nitrate gave 0.86 g of metal sulphate. Calculate the equivalent weight of metal.

3g of an oxide of a metal is converted to chloride completely and it yielded 5g of chloride. The equivalent weight of metal is

0.635 g of a metal gives on oxidation 0.795g g of its oxide. Calculate the equivalent mass of the metal.

4 g of copper was dissolved in concentrated nitric acid. The copper nitrate on strong heating gave 5 g of its oxide. The equivalent weight of copper is

2 g of a metal in H_(2) SO_(4) gives 4.51 g of the metal sulphate. The specific heat of metal is 0.057 cal g^(-1) . Calculate the valency and atomic weight of metal.

The atomic weight of a metal (M) is 27 and its equivalent weight is 9, the formula of its chloride will be

1.878 g of MBr_(X) when heated in a stream of HCl gas was completely converted to chloride MCl_(X) which weighted 1.0 g The specific heat of metal is 0.14 cal g^(-1) . Calculate the molecular weight of the metal bromide.