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100 mL of mixture of NaOH and Na(2)SO(4)...

`100 mL` of mixture of `NaOH` and `Na_(2)SO_(4)` is neutralised by `10 mL` of `0.5 M H_(2) SO_(4)`. Hence, NaOH in `100 mL` solution is

A

`0.2 g`

B

`0.4 g`

C

`0.6 g`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
`Na_(2) SO_(4)` does not react,
`N (NaOH) = 0.1 = 4 gL^(-1)`
`= 0.4 g` per `100 mL`
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