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Mole fraction of ethanol is ethanol wate...

Mole fraction of ethanol is ethanol water mixture is 0.25. Hence, the percentage concentration of ethanol by weight of mixture is

A

0.25

B

0.75

C

0.46

D

0.54

Text Solution

Verified by Experts

The correct Answer is:
C
`chi_(2) = (n_(2))/(n_(1) + n_(2)) = 0.25` (ethanol)(solute) `(Mw_(2) = 46 g)`
`chi_(1) = (n_(1))/(n_(1) + n_(2)) = 0.75` (water) (solvent) `(Mw_(1) = 18 g)`
`(chi_(1))/(chi_(2)) = (n_(1))/(n_(2)) = (3)/(1) implies (W_(1) xx Mw_(2))/(Mw_(1) xx W_(2)) = (3)/(1)`
`(W_(1) xx 46)/(18 xx W_(2)) = 3`
`(W_(1))/(W_(2)) = 1.17`
`:. (W_(2))/(W_(1) + W_(2)) = 0.46`
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