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Consider the ionisation of H(2) SO(4) as...

Consider the ionisation of `H_(2) SO_(4)` as follow"
`H_(2) SO_(4) + 2H_(2)P rarr 2H_(3) O^(o+) SO_(4)^(2-)`
The total number of ions furnised by `100 mL` of `0.1 M` `H_(2)SO_(4)` will be

Text Solution

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The correct Answer is:
C
1 mol `H_(2) SO_(4) -= 2 "mol" H_(3)O^(O+) -= 1 "mol" SO_(4)^(2-)`
`((100)/(1000) xx 0.1 = 0.01) -= 2 xx 0.01 + 0.01 = 0.03 "mo"`
`= 0.18069 xx 10^(23)`
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