If 100 mL of H(2) SO(4) and 100 mL of H(...

If `100 mL` of `H_(2) SO_(4)` and `100 mL` of `H_(2)O` are mixed, the mass percent of `H_(2) SO_(4)` in the resulting solution `(d_(H_(2)SO_(4)) = 0.09 g mL^(-1), d_(H_(2)O) = 1.0 mL^(-1))`

A

90

B

47.36

C

50

D

60

Verified by Experts

The correct Answer is:

B

`X_(H_(2)SO_(4)) = (100 xx 0.9)/(100 xx 0.9 + 100 xx 1) = (90)/(190) = 0.4736`
% mass of `H_(2)SO_(4) = 43.36%`

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