Home
Class 11
CHEMISTRY
12.5 mL of a solution containing 6.0 g o...

`12.5 mL` of a solution containing `6.0 g` of a dibasic acid in `1 L` was found to be neutralized by `10 mL` a decinormal solution of `NaOH`. The molecular weight of the acid is

A

150

B

120

C

110

D

75

Text Solution

Verified by Experts

The correct Answer is:
A

Dibasic acid `-= NaOH`
`12.5 mL` `10 mL xx 0.1 N = 1 mEq`
Strength of dibasic acid ` = 6 gL^(-1)`
mEq of acid = mEq of `NaOH`
`12.5 xx N = 1 mEq`
`(12.5 xx 6 xx 1000)/((Mw_(2))/(2) xx 1000) = 1`
`:. Mw` (acid) `= 150`
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution containing 8.6 g urea in 1 L was found to be isotonic with 5%(weight//volume) solution of an organic non-volatile solute. The molecular weight of latter is

Calculate the molarity of a solution containing 5 g of NaOH in 450 mL solution.

A solution containing 4 g of a non-volatile organic solute per 100 mL was found to have an osmotic pressure equal to 500 cm of mercury at 27^(@)C . The molecular weight of solute is

A solution containing 4.2 g of urea in 500 ml was found to be isotonic with a 5% ( wt./vol.)solution of an organic non-volatile solute. The molar mass of the solute is

10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be

0.45 g of an acid ( mol. Mass = 90 ) is neutralised by 20 mol of 0.5 N NaOH solution. The basicity of the acid is :

200 cm^(3) of a solution of a dibasic acid contains 1.512 g of the acid and the normality of the solution is 0.12. Calculate (i) the equivalent mass and (ii) the molecular mass of the acid.