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Mixture X = 0.02 mol of [Co (NH3)5 SO4] ...

Mixture X = 0.02 mol of `[Co (NH_3)_5 SO_4]` Br Brand 0.02 mol of `[Co (NH_2)_5 Br] SO_4` was prepared in 2L of solution.
1 L of mixture X + excess of `AgNO_3 to Y `
1 L of mixture X + excess of `BaCl_2 to Z`
Number of moles of Y and Z are :

A

0.01,0.01

B

0.02,0.01

C

0.01,0.02

D

0.02,0.02

Text Solution

Verified by Experts

The correct Answer is:
A

A mixture `X` containing 0.02 mol of `[Co(NH_(3))_(5) SO_(4) Br` and 0.02 mol of `[CO(NH_(3))_(5) Br]SO_(4)` was prepared in `2 L` of solution of `[Co(NH_(3))_(5) SO_(4) Br 0.01` mol of `[Co(NH_(3))_(5) Br]SO_(4)`.
`1 L` of mixture `X +` excess `AgNO_(3) rarr 0.01 "mol" AgBr`
`1 L` of mixture `X +` excess `BaCl_(2) rarr 0.01 "mol" BaSO_(4)`
This is according to the following reactions taking place:
`[Co(NH_(3))_(5) Br] SO_(4) + AgNO_(3) rarr`
`[Co(NH_(3))_(5) SO_(4)]NO_(3) + AgBr darr`
`Co (NH_(3))_(5) Br]SO_(4) + BaCl_(3) rarr`
`[Co(NH_(3))_(5) Br] Cl_(2) + BaSO_(4) darr`
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