Home
Class 11
CHEMISTRY
The total number of electrons in 18 mL o...

The total number of electrons in 18 mL of water (density = 1 g `mL^(-1)` ) is

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
The total numbe of electrons present in `18 mL` of water is `6.023 xx 10^(24)`.
Number of electron in one molecules of `H_(2) O` is `2 + 8 = 10`
Denisty = 1
`18 mL` means `18 g`
Moles `= (18)/(18) = 1`
Moles `= 6.023 xx 10^(23)`
Electrons `= 6.023 xx 10^(23) xx 10 = 6.023 xx 10^(24)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The volume of one molecule of water is (density of water = 1 g ml^(-1) ) about

Volume occupied by one molecule of water (density = 1 g cm^-3 ) is :

A solution contains 410.3 g H_(2) SO_(4) per litre of the solution at 20^(@)C . If the density = 1.243 g mL^(-1) , what will be its molality and molarity?

Calculate the molality (m) of 3 M solution of NaCl whose density is 1.25 g mL^(-1) .

Commercially available concentrated HCI contains 38.0% HCl by mass (density = 1.19 g mL^(-1) ). The molarity of the solution is

Calculate the total number of electrons present in 3.2 g of oxygen gas.