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4.2 g of a metallic carbonate MCO(3) was...

`4.2 g` of a metallic carbonate `MCO_(3)` was heated in a hard glass tube and `CO_(2)` evolved was found to have `1120 mL` of volume at `STP`. The `Ew` of the metal is

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The correct Answer is:
A, B
`Pv = nRT = (W)/(Mw) RT`
`:. (700)/(760) xx (1336)/(1000) = (W)/(44) xx 0.0821 xx 300`
or `W = 2.198 g CO_(2)`
The molecular mass of any metal carbonate is `2E + 60`,
Where `E` is the equivalent mass of the metal. So
`(2E + 60)/(4.215) = (44)/(2.193)`
`E = 12.188 g`
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