Calculate the amount of calcuium oxide r...

Calculate the amount of calcuium oxide required when it reacts with `852 g` of `P_(4) O_(10)`.

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The correct Answer is:

A

`6CaO + P_(4) O_(10) rarr 2Ca_(3) (PO_(4))_(2)`
`6CaO -= P_(4)O_(10)`
`(6 (40 + 16))/(W) = ((31 xx 4) + (16 xx 10))/(852)`
or `W = 1008 g`

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