In the reaction: Cr(2)O(7)^(2-) + 14H^...

In the reaction:
`Cr_(2)O_(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3H_(2)O + 3I_(2)`
Which element is reduced?

A

`Cr`

B

`H`

C

`O`

D

`I`

Verified by Experts

The correct Answer is:

A

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In the reaction: Cr(2)O(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3...
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