The oxidation number of `Cr` is `+6` in

Options

A. `FeCr_(2)O_(4)`
B. `KCrO_(3)Cl`
C. `CrO_(5)`
D. `[Cr(OH)_(4)]^(ө)`

Answer

B, C

Explanation

`Fe^(2+)(Cr_(2)O_(4))^(2-): "Oxidation state of" Cr= +3`
b. `K^(o+)[CrO_(3)Cl]^(ө): "Oxidation state of" Cr= +6`

Oxidation state of `Cr= +6`. ( Two peroxo linkage)
d. `[Cr(OH)_(4)]^(ө): "Oxidation state of" Cr= +3`