Which of the following have been arranged in decreasing order of oxidation number of sulphur ?

Options

A. `H_(2)S_(2)O_(7) gt Na_(2)S_(4)O_(6) gt Na_(2)S_(2)O_(3) gt S_(8)`
B. `SO^(2+) gt SO_(4)^(2-) gt SO_(3)^(2-) gt HSO_(4)^(ө)`
C. `H_(2)SO_(5) gt H_(2)SO_(3) gt SCl_(2) gt H_(2)S`
D. `H_(2)SO_(4) gt SO_(2) gt H_(2)S gt H_(2)S_(2)O_(8)`

Answer

A, C

Explanation

`{:(H_(2)S_(2)O_(7):,2+2x-14=0implies,x=6,,),(Na_(2)S_(4)O_(6):,2+4x-12=0implies,x=2.5,,),(Na_(2)S_(2)O_(3):,2+2x-6=0implies,x=2,,),(,S_(8):8x=0impliesx=0,,,):}]underset("state if S")("Oxidation")`
c. `H_(2)SO_(5)` (Peroxo linkage)
Oxidation state of `S= +6`
`H_(2)SO_(3): 2+x-6=0`
Oxidation state of `S= +4`
`SCl_(2):x-2=0`
Oxidation state of `S= +2`
`H_(2)S:2+x=0`
Oxidation state of `S= -2`