Home
Class 11
CHEMISTRY
The number of moles of K(2)Cr(2)O(7) red...

The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions is

A

`1//3`

B

`3`

C

`1//6`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
A
`(6e^(-)+Cr_(2)O_(7)^(2-)rarr2Cr^(3+))`
`Sn^(2+)rarrSn^(4+)+2e^(-)`
Equivalent of `Cr_(2)O_(7)^(2-)= "Equivalent of" Sn^(2+)`
`(n=6)` , `(n=2)`
`implies1 Eq= 1Eq`
`(1)/(6) mol =(1)/(2) mol`
`(1)/(3) "mol of" Cr_(2)O_(7)^(2-)= 1 "mol of" Sn^(2+)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Oxidation number of chromium in K_(2)Cr_(2)O_(7) is

How many moles of acidified K_(2)Cr_(2)O_(7) is required to liberate 6 moles of I_(2) from an aqueous solution of I^(-) ?

In Cr_(2)O_(7)^(2-) :

The number of moles of electron required to reduce 0.2 mole of Cr_(2)O_(7)^(2-) to Cr^(3+)

How is K_(2)Cr_(2)O_(7) manufactured from chromite ore.