Coordination number and oxidation state of Cr in `K_(3)[Cr(C_(2)O_(4))_(3)] ` are respectively :

Options

A. `4 and +2`
B. `6 and +3`
C. `3` and `-3`
D. `3` and `0`

Answer

B

Explanation

Coodination number
= Number of ligands `xx` denticity
`3xx2` ( bidendate)
`=6`
`overset(+3)K[overset(+3)(Cr)overset(-2xx3)((C_(2)O_(4))_(3))]^(3-) :. "Oxidation state of " Cr= +3`.