The oxidant number of Fe in Na(2) [Fe(CN...

The oxidant number of `Fe` in `Na_(2) [Fe(CN)_(5)NO]` is

A

`+2`

B

`+1`

C

`+3`

D

`-2`

Verified by Experts

The correct Answer is:

A

`overset(+)Na_(2)[overset(+2)(Fe)overset(-5)((CN))_(5)overset(+1)(NO)]^(2-)`
Oxidation state of `Fe= +2`

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