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Oxidation number of Cl in CaOCl(2) is...

Oxidation number of Cl in `CaOCl_(2)` is

A

`-1 and +1`

B

`+2`

C

`-2`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`Ca^(2+)(Ocl^(-))Cl^(1-)`
`Ocl^(ө): - 2+x= -1 implies x= +1`
`Cl^(ө): - 1`
Oxidation states of `Cl` are `-1` and `+1`.
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