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The oxidation state of S in H(2)S(2)O(8)...

The oxidation state of `S` in `H_(2)S_(2)O_(8)` is

A

`+2`

B

`+4`

C

`+6`

D

`+7`

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(2)S_(2)O_(8)`: It is peroxodisulphuric acid. So oxidation state of `S= +6`
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