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A sample of a crystalline solid scatters...

A sample of a crystalline solid scatters a beam of X-rays of wavelength `70.93` pm at an angle `2 theta` of `14.66^(@)`. If this is a second-order reflection `(n = 2),` calculate the distance between the parallel planers of atoms from which the scattered beam appears to have been reflected.

Text Solution

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We know that: `n lambda = 2d sin theta`
`2 theta = 14.66^(@)` or `theta = 7.33^(@)`
`lambda = 70.93 "pm" = 70.93 xx 10^(-12)m`
`:. d = (n lambda)/(2 sin theta) = (2 xx 70.93 xx 10^(-12))/(2 sin 7.33^(@))m`
`= 556.3 xx 10^(-12)m`
`= 556.3` pm
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