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CsCl has bc c arrangement and its unit c...

`CsCl` has `bc c` arrangement and its unit cell edge length is `400` pm. Calculate the interionic distance in `CsCl`.

Text Solution

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The `bc c` arrangement of `CsCl` is shown in the figure below. The aim is to find half of the body diagonal `AE`. If the edge of the unit cell is `a`, then

`CE = sqrt(a^(2) + a^(2)) = sqrt2a`
`:. AE = sqrt((sqrt2a)^(2) + a^(2) = sqrt3a`
`= sqrt3 xx 400`
`:.` Interionic distance `= (1)/(2)AE`
`= sqrt3 xx 200 = 346.6`
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