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For the spinel structure (MgAl(2)O(4)), ...

For the spinel structure `(MgAl_(2)O_(4))`, the correct statement is//are

A

`50% OV_(s)` are occupied by ions.

B

`Al^(3+)` is equally distributed in `TVs` and `OVs`.

C

Oxide ions occupy ccp lattice.

D

`12.5% TVs` are occupied by ions.

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
For spinel structure, `O^(2-)` ions from fcc arrangement.
`:. `Number of `O^(2-)` ions `= 4`.
Number of `TV = 8`, Number of `OV = 4`
Number of `Mg^(2+)` ions `= 1/8 = TV = 1/8 xx 8 = 1`
Number of `Al^(3+)` ions `= 1/2 xx OV = 1/2 xx 4 = 2`
So, `50% OVs` are occupied and `1//8` lth, ie., `12.5% TV` occupied.
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