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In the closest packing of atoms...

In the closest packing of atoms

A

The size of `TV` is greater than that of `OV`.

B

The size of `TV` is smaller than that of `OV`.

C

The size of `TV` is equal to that of `OV`.

D

The size of `TV` may be greater or smaller or equal to that of `OV` depending upon the size of atoms.

Text Solution

Verified by Experts

The correct Answer is:
B
For a given radius of anion `(r_(ɵ))`
Radius ratio for `OV` and `TV` is as follows:
`((r_(o+))/(r_(ɵ)))_(OV) gt ((r_(o+))/(r_(ɵ)))_(TV)`
`[{:("For" OV,(r_(o+))/(r_(ɵ))=0.414-0.732),("For" TV,(r_(o+))/(r_(ɵ))=0.225-0.414):}]`
Hence, size of `OV` is larger than that of `TV`.
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