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The density of an ionic compounds (Mw =...

The density of an ionic compounds `(Mw = 58.5)` is `2.165 kg m^(-3)` and the edge length of unit cell is `562` pm, then the closest distance between `A^(o+)B^(ɵ)` and `Z_(eff)` of unit cell is

A

`281` pm, `4`

B

`562` pm, `2`

C

`562` pm, `4`

D

`281` pm, `2`

Text Solution

Verified by Experts

The correct Answer is:
A
`rho=(Z_(eff)xxMw)/(a^(3) xx N_(A))`
`2.165 kg m^(-3) = (Z_(eff) xx 58.5 xx 10^(-3)kg mol^(-1))/((562 xx 10^(-12))^(3)m^(3) xx 6 xx 10^(23)"atoms")`
`:. Z_(eff) = 4` (fcc-type structure).
For `fcc`,
`d_(A^(o+))-B^(ɵ) = (a)/(2) = (562)/(2) = 281 "pm"`
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