Home
Class 12
CHEMISTRY
A metal of density 7.5 xx 10^(3) kg m^(-...

A metal of density `7.5 xx 10^(3) kg m^(-3)` has an fcc crystal structure with lattice parameter `a = 400 pm`. Calculater the number of unit cells present in `0.015 kg` of metal.

A

`6.250 xx 10^(22)`

B

`3.125 xx 10^(23)`

C

`3.125 xx 10^(22)`

D

`1.563 xx 10^(22)`

Text Solution

Verified by Experts

The correct Answer is:
C
The volume availagble `= (0.015)/(7.5 xx 10^(3))`
`("Number of unit cells") xx (400 xx 10^(-12))^(3) = (0.015)/(7.5 xx 10^(3))`
`rArr` Number of unit cell `= 3.125 xx 10^(22)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Aluminium crystallizes in a ccp structure. Its metallic radius is 125pm. The number of unit cells in 1.00 cm^(3) of Al are

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. Calculate the edge length of the unit cell of the metal.

A metal X ( at. Mass = 60) has a body centred cubic crystal structure. The density of the metal is 4.2 g cm^(-3) . The volume of unit cell is

Aluminium crystallizes in FCC structure. Atomic radius of the metalics 125 pm. Calculate the edge length of the unit cell.

Aluminium metal has a density of 2.72 g cm^(-3) and crystallizes in a cubic lattice with an edge of 404 pm. Which is//are correct?

The density of chromium metal is 7.2 g cm^(-3) . If the unit cell is cubic with edge length of 289 pm. Calculate the number of atoms per unit cell. (Atomic mass = 51.79)

An element crystallizes in a structure having fcc unit cell of an edge 200 pm. Calculate the density if 200 g of this element contains 24 xx 10^(23) atoms.

Aluminium metals forms a cubic face centred close packed crystal structure. Its atomic radius is 125xx10^(-12) m. The length of the side of the unit cell is