Home
Class 12
CHEMISTRY
A TV in fcc is formed by atoms at...

A `TV` in fcc is formed by atoms at

A

`3` corners `+ 1` face centre

B

`3` face centres `+ 1` corner

C

`2` face centres `+ 2` corners

D

`2` face centres `+ 1` corner `+ 1` body centre

Text Solution

Verified by Experts

The correct Answer is:
B
A TV in fcc is formed by `3` face centre atoms and one corner atom. In total `8` such tetrahedorns are possible.
Promotional Banner

Similar Questions

Explore conceptually related problems

A compound is formed by elements A and B. This crystallizes in the cubic structure where the A atoms are at the corners of the cube and B atoms are at the body centres. The simplest formulta of the compound is :

A compound is formed by elements A and B . This crystallises in the cubic structure where the A atoms are the corners of the cube and B atoms are at the body centres . The simplest formula of the compound is

In silicon crystal, Si atoms from fcc arrangement where 4 out 8 TVs are alos occupied by Si atoms. Z_(eff) of unit cell is

In spinel, Mg^(2+) is present in one-eighth of TVs in an fcc lattice of oxide ions and Al^(3+) ions are present in half of the OVs . The Formula of spinel is

Mention two conditions for an atom to form an ionic bond.

Mention the type of bond formed between the atoms having same electronegativity.

Mention the type of bond formed between the atoms having different electronegativity.

The distance between any two TV_(s) formed on any body diagonal of a closest packed structure is = x xx a , where a is the edge length of closest packed structure. the value of x = ……… .

A compound formed by elements A and B has a cubic structure in which A atoms are at the corners of the cube and B atoms are at the face centres. The formula of the compound is :