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In the structure of diamond, carbon atom...

In the structure of diamond, carbon atoms appear at

A

`0, 0, 0`, and `(1)/(2), (1)/(2), (1)/(2)`

B

`(1)/(4), (1)/(4), (1)/4`, and `(1)/(2), (1)/(2), (1)/(2)`

C

`0, 0, 0`, and `(1)/(4), (1)/(4), (1)/(4)`

D

`0, 0, 0`, and `(3)/(4), (3)/(4), (3)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
The space lattice of diamond is `fcc`. The primitive bassis has two identical atoms at `0,0,0` and `1/4,1/4,1/4` associated with each point of the fcc lattice as shown in the figure.
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