Home
Class 12
CHEMISTRY
Assertion (A) : In sodium chloride cryst...

Assertion (A) : In sodium chloride crystal, `Na^(o+)` ions occupy `OVs` while `Cl^(ɵ)` ions occupy vertices of octahedron.
Reason (R ) : The radius ratio of `Na^(o+) : Cl^(ɵ)` lies between `0.4` and `0.7`.

A

If both `(A)` and `(R)` are correct, and `(R)` is the correct explanation of `(A)`

B

If both `(A)` and `(R)` are correct, but `(R)` is not the correct explanation of `(A)`

C

If `(A)` is correct, but `(R)` is incorrect.

D

If both `(A)` is incorrect, but `(R)` is correct.

Text Solution

Verified by Experts

The correct Answer is:
D

Correct (A): `Na^(o+)` ions occupy all `OVs` but `Cl^(ɵ)` ions occupy lattice points `("corner" + "face centres")`.
(R) is correct, for `OV, r_(o+) + r_(ɵ) = 0.414 - 0.732`
Promotional Banner

Similar Questions

Explore conceptually related problems

Assertion (A) : In sodium chloride crystal, the coordination number of Na^(o+) IS 6 . Reason (R ) : The sodium atom is smaller than chlorine atom.

In the sodium chloride structure each Na_(o+) ion is surrounded by six Cl^(ɵ) ions nearest neighbours and ……….. Na^(o+) ions next nearest neighbours.

Assertion (A) : CsCl crystal, the coordination number of Cs^(o+) ion is 8 . Reason (R ) : Cl^(ɵ) ion in CsCl adopt bcc type of packing,

Assertion (A) : In the rock salt type structure, all the OV_(s) are occupied by Na^(o+) ions. Reason (R ) : Number of OV_(s) = Number of Cl^(ɵ) ions in the packing.

If the length of the body for CsCl which crystallizes into a cubic strructure with Cl^(Θ) ions at the corners and Cs^(o+) ions at the centre of the unit cell is 7 Å and the radius of he Cs^(o+) ions is 1.69Å , what is the radius of Cl^(ɵ) ions?

In an LiI crystal, I^(ɵ) ions from a cubical close-packed arrangement, a nd Li^(o+) ion occupy octahedral holes. What is the relationship between the edge length of the unit cells and radii of the I^(ɵ) ions if a = 60 "pm".

The "OLIVINE" series of minerals consists of crystal in which Fe^(2+) and Mg^(2+) ions may substitute for each other causing susbstitutional impurity defects without changing the volume of unit cell. In "OLIVINE" series of minerals, O^(2-) ions exist as fcc with Si^(4+) occupying one-fourth of OVs and divalent metal ions occupying one-fourth of OVs and divalent metal ions occupying one-fourth of TVs . The density of "forsterite" (magnesium silicate) is 3.21 g cm^(-3) land that of "fayalite" (ferrous silicate) is 4.34 g cm^(-3) . If in "forsterite mineral" bivalent Mg^(2+) ions are to be replaced by unipositive Na^(o+) ions, and if Na^(o+) ions are occupying half of TV_(s) in fcc lattice, the arrangement of rest of the constituents is kept same, then the formula of the new solid is:

The "OLIVINE" series of minerals consists of crystal in which Fe^(2+) and Mg^(2+) ions may substitute for each other causing susbstitutional impurity defects without changing the volume of unit cell. In "OLIVINE" series of minerals, O^(2-) ions exist as fcc with Si^(4+) occupying one-fourth of OVs and divalent metal ions occupying one-fourth of OVs and divalent metal ions occupying one-fourth of TVs . The density of "forsterite" (magnesium silicate) is 3.21 g cm^(-3) land that of "fayalite" (ferrous silicate) is 4.34 g cm^(-3) . The formula of "fayalite mineral" is

The density of NH_(4)Cl is 1.534 g cm^(-3) . It crystallizes in the CsCl lattice. a. Calculate the length of the length of the edge of NH_(4)Cl unit cell. b. Calculate the shortest distance between a NH_(4)^(o+) ion and a Cl^(ɵ) ion. c. Calculate the radius of NH_(4)^(o+) ion if the radius of the Cl^(ɵ) ion is 181 pm

O_(2-) ions are arranged in ccp in spinel structure. A^(2+) ions occupy 1//8 of TV_(s) and B^(o+) ions occupy half of OV . The void volume of unit cell = 0.11 Å . Find the value of A ?