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The arrangement of X^(ɵ) ions around A^(...

The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is 250 pm, the radius of `A^(o+)` is

A

104 pm

B

125 pm

C

183 pm

D

57 pm

Text Solution

Verified by Experts

The correct Answer is:
A
According to the given figure, `A^(o+)` is present in the octahedral void of `X^(ɵ)`. The limiting radius in octahedral void related to the radius of sphere as
`r_("void") = 0.414 r_("sphere")`
`r_(A^(o+)) = 0.414 r_(x^(ɵ))`
`= 0.414 xx 250 "pm"`
`= 103.5 approx 104 "pm"`
Hence (a) is correct.
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