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In a cubic,A atoms are present on altern...

In a cubic,`A` atoms are present on alternative corners, `B` atoms are present on alternate faces, and `C` atoms are present on alternalte edges and body centred of the cube. The simplest formula of the compound is

A

`A_(2)BC_(4)`

B

`AB_(2)C_(4)`

C

`ABC_(4)`

D

`ABC_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Number of `A` atoms at alternate corners
`= 4` corner `xx (1)/(8)` per corner share `= (1)/(2)`
Number of `B` atoms at alternate face
`= 2` faces `xx (1)/(2)` per face center share `= 1`
Number of `C` atoms at alternate edges and at body centre
`=` (`4` edges `xx (1)/(4)` per edge centre share)
`+ 1` atom at body centre
`= 1 + 1 = 2`
Thus, formula `A_((1)/(2))B_(1)C_(2)`
Simplifying, `AB_(2)C_(4)`.
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