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If atoms are removed from half of the ed...

If atoms are removed from half of the edge-centred `OV_(s)` in `RbBr`, then the molecular formula of unit cell is

A

`Rb_(2)Br_(2)`

B

`Rb_(1.5)Br_(3)`

C

`Rb_(2.5)Br_(4)`

D

`Rb_(4)Br_(2.5)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Br^(ɵ)` in closest packed structure (e.g., fcc or ccp).
`:.` Number of `Br^(ɵ) = 4` (corner `+` face centre `= 1 + 3 = 4`).
Number of alternate `OVs = 6 xx (1)/(4)` (Edge center share)
`= (3)/(2) = 1.5`
Number of `Rb^(o+)` intially `=` Edge centre `+` body centre
`= 12 xx (1)/(4) + (1)/(1) = 4`
Number of `Rb^(o+)` ion left `= 4 - 1.5 = 2.5`
thus, formula is `Rb_(2.5)B_(4)`.
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