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Calculate the vapour pressure lowering o...

Calculate the vapour pressure lowering of a `0.1 m` aqueous solution of non-electrolyte at `75@C`.
`DeltaH = 9.720 Kcal mol^(-1)` , `P_(2)` = 742.96 torr

Text Solution

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The vapour pressure of pure water, `P_(A)^(@)`, at `75^(@)C` is
`"log" P_(2)/P_(1)=(DeltaH^(@))/(2.303R) (1/T_(1) - 1/T_(2))`
`= 9720/2.30 xx 1.978 (1/348 - 1/373) = 0.410`
`P_(2)/P_(1) = 2.21 `, `P_(1) = 296` torr
The vapour pressure lowering due to `0.100 m` solute is
`DeltaP = (mMw_(A)P_(A)^(@))/(1000) = (0.1 xx 18 xx 296)/(1000)=0.533`
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