Home
Class 12
CHEMISTRY
Calculate the vapour pressure of an aqu...

Calculate the vapour pressure of an aqueous solution of `1.0` molal glucose solution at `100^(@)C`.

Text Solution

Verified by Experts

Molarlity =`(W_(2))/(Mw_(2)xxW_(1)) xx 1000`
where `W_(2)` = mass of solute in grams,
`W_(1)` = mass of solvent in grams
`1.0 = (W_(2) xx 1000) /(Mw_(2) xx W_(1))`
`(K/W_(1) = K') = 1.0 /1000 = 0.001`
Applying Raoult's law for dilute solution,
`(P^(@) - P_(S)) / P^(@) = W_(2) / (Mw_(2) xx W_(1)) xx Mw_(1)` `[Mw_(1) = 18]`
`(760 - P_(S))/(760) = 0.001 xx 18`
`=760-13.68`
`746.32 mm Hg`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the vapour pressure lowering of a 0.1 m aqueous solution of non-electrolyte at 75@C . DeltaH = 9.720 Kcal mol^(-1) , P_(2) = 742.96 torr

Calculate the vapour pressure of an aqueous solution which contains 5 mass per per cent of urea . The vapour pressure of pure water is 23.5 mm Hg . The molar mass of urea is 60 .

lowering of vapour pressure due to a solute in 1 molal aqueous solution at 100^(@)C is a. 13.44 mm Hg ,b. 14.14 mm Hg ,c. 13.2 mm Hg ,d. 35.2 mm Hg

Vapour pressure of a solution containing a non volatile solute is

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

Assuming ideal behaviour, calculate the pressure of 1.0 molal solution of a non-volatile molecular solute in water at 50@C . The vapour presure of water at 50@C is 0.222 atm .

Mole fraction of the solute in a 1.00 molal aqueous solution is

Relative lowering of vapour pressure of al dilute solution of gluscose dissolved in 1kg of water is 0.002.The molality of the solution is

Calculate the vapour pressure of the solution. The molefraction of the solute is 0.25. The vapour pressure of the pure solvent is 0.8atm.