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The ebullioscopic constant for benzene i...

The ebullioscopic constant for benzene is `2.52 K Kg mol^(-1)`. A solution of an organic substance in benzene boils at `0.125^(@)C` higher than benzene. Calculate the molality of solution?

A

10

B

1

C

2

D

0.05

Text Solution

Verified by Experts

The correct Answer is:
D
Given values are:
`K_(b) = 2.52 K m^(-1)` or `2.52 K kg m^(-1)`
`DeltaT_(b) = 0.125^(@)C`
Using the relation,`DeltaT_(b) =K_(b)m`
`:. M = (Delta_(b)T) / K_(b)`
`= (0.125)/(2.52)= 0.05`
Hence, molality of the solution is `0.05 m`.
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