`300 cm^(3)` of an aqueous solution contains `1.26 g` a polymer. The osmotic pressure of such solution at `300 K` is found to be `1.26xx10^(-3)` bar. Calculate the molar mass of the polymer.

Explanation

`piV=(W_(B))/(Mw_(B))RT`
`Mw_(B)=(W_(B))/(V)xx(RT)/(pi)`
`(1.26)/(0.3)xx(0.083xx300)/(1.26xx10^(-3))`
`=83000 g mol^(-1)`