Home
Class 12
CHEMISTRY
A solution is prepared by dissolving 1.0...

A solution is prepared by dissolving `1.08 g` of human serum albumin, a protein obtained from blood plasma, in `50 cm^(3)` of aqueous solution. The solution has an osmotic pressure of `5.85 mm Hg` at `298 K`.
a. What is the molar mass of albumin ?
b. What is the height of water column placed in solution ?
`d_((H_(2)O)) =1 g cm^(-3)`

Text Solution

Verified by Experts

a. The molar massof albumin can be calculated using the following relation
`Mw_(B)=(W_(B)xxRT)/(piV)` ….(i)
Given,`W_(B)=1.08 g`,`R=0.0821 L atm K^(-1) mol^(-1)`
`T=298 K , pi=(5.85)/(760) atm,V=(50)/(1000) = 0.005 L`
Substituting these values in Eq.(i), we get
`Mw_(B)=(1.08xx0.0821xx298)/((5.85//760)xx0.05)=68655 g mol^(-1)`
b. `pi=hdg`
`(5.85)/(760)xx101325=hxx1xx10^(-3)xx9.8`
[1 atm = 101325 Pa]
`:. h=7.958 xx10^(-2) m =7.958 cm`
Promotional Banner

Similar Questions

Explore conceptually related problems

3 gram of non-volatile solute in a 1000 cm^(3) of water shows an osmotic pressure of 2 bar at 300K. Calculate the molar mass of the solute (R=0.0853" L bar "K^(-1)mol^(-1)) .

At 300 K , 36 g of glucose present per litre in its solution has an osmotic pressure of 4.98 bar . If the osmotic pressure of the solution is 1.52 bar at the same temperature, what would be its concentration?

300 cm^(3) of an aqueous solution contains 1.26 g a polymer. The osmotic pressure of such solution at 300 K is found to be 1.26xx10^(-3) bar. Calculate the molar mass of the polymer.

If 1.71 g of sugar (molar mass=342) is dissoved in 500 cm^(3) of a solution at 300K. What will be its osmotic pressure?

2.5 g of a substance is present in 200 mL of solution showing the osmotic pressure of 60 cm Hg at 15^(@)C . Calculate the molecular weight of substance.What will be the osmotic pressure if temperature is raised to 25^(@)C ?

A solution of sucrose (molar mass =342) is prepared by dissolving 68.4 g in 1000 g of water. Calculate The osmotic pressure at 273 K.

A 1.24 M aqueous solution of KI has density of 1.15 g cm^(-3) . Answer the following questions about this solution: What is the freezing point of the solution if KI is completely dissociated in the solution?

A solution containing 6 g of a solute dissolved in 250 cm^(3) of water gave an osmotic pressure of 4.5 atm at 27^(@)C . Calculate the boiling point of the solution.The molal elevation constant for water is 0.52^@ C per 1000 g.

A solution was prepared by dissolving 6.0 g an organic compound in 100 g of water. Calculate the osmotic pressure of this solution at 298 K ,when the boiling point of the Solution is 100.2^(@)C . ( K_(b) for water = 0.52 K m^(-1) ), R=0.082 L atm K^(_1) mol^(-1) )