At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?

Explanation

The given values are
`T=300 K`
`W_("solute")=36 g`
`pi_(1)=4.98` bar
`pi_(2)=1.52` bar
`V_("solution")=1 L`
According to Van,t Hoff equation,
`pi=CRT`
`C_(1)=(36)/(180)M ,C_(2) = ?`
`:. 4.98` bar `= (36)/(180)RT` …(i)
`1.52` bar `= C_(2)RT` ... (ii)
Dividing Eq. (ii) by Eq.(i),
`(C_(2)/36)xx(180)=1.52/4.98`
`:. C_(2)=(1.52)/(4.98)xx(36)/(180)=0.061 M`
Thus, the concentration of second solution is `0.061 M`.