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What will be the osmotic pressure of 0.1...

What will be the osmotic pressure of `0.1 M` monobasic acid its `pH` is `2` at `25^(@)C`?

Text Solution

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`HA hArr H^(o-)+A^ө`
`[Ho+] = C alpha=10^(-2)M`
`:.alpha=10^(-2)/0.1=10^(-1)=0.1`
`:.`Total particles in solution =`1+alpha=1+0.1=1.1`
Now,`pi=CRT(1+alpha)`
`0.1xx0.0821xx298xx1.1=2.69 atm`
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