Home
Class 12
CHEMISTRY
0.1 M aqueous solution of MgCl(2) at 300...

`0.1 M` aqueous solution of `MgCl_(2)` at `300 K` is `4.92 atm`. What will be the percentage ionination of the salt?
a.`49%` , b. `59%` ,c.`79%` d. `69%`

Text Solution

Verified by Experts

a.`pi=iCRT`
`4.92=ixx0.1xx0.0821xx300`
`i=1.99`
`alpha=(i-1)/(n-1)=(1.99-1)/(3-1)=(0.99)/(2)=0.49`
Perecentage of ionization=`49%`
Promotional Banner

Similar Questions

Explore conceptually related problems

0.06% (w/v) aqueous solution of urea is isotonic with:

0.85% aqueous solution of NaNO_(3) is apparently 90% dissociated . The osmotic pressure of solution at 300 K is

A 0.2 molal solution of KCl freezes at -0.68^(@)C . If K_(f) for H_(2)O is 1.86 , the degree of dissociation of KCl is a. 85% , b. 83% , c. 65% , d. 90%

0.2 m aqueous solution of a weak acid (HX) is 20% dissociated. The boiling point of this solution is ( K_(b) for water = 0.52 Km^(-1) )

The freezing point of 1% aqueous solution of calcuim nitrate will be