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The Van't Hoff factor of Hg(2)Cl(2) in i...

The Van't Hoff factor of `Hg_(2)Cl_(2)` in its aqueous solution will be (`Hg_(2)Cl_(2)` is `80%` ionized in the solution)
a.`1.6` , b.`2.6` ,c.`3.6` ,d.`4.6`

Text Solution

Verified by Experts

`underset(n=3)(Hg_2Cl_2)hArrHg_2^(2+)+2Cl^(ө)`
` n=3`
`alpha=(i-1)/(n-1) rArr 0.8 = (i-1)/(3-1) rArr i=2.6`
Alternate method to calculate (i)
`i=("Number of ions" xx alpha)+(1-alpha)`)
`=(3xx0.8)+(1-0.8)` [`alpha=80%` or `0.8`]
`=2.4+0.2=2.6`
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