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A 4% solution of sucrose C(12)H(22)O(11)...

A `4%` solution of sucrose `C_(12)H_(22)O_(11)` is isotonic with `3%` solution of an unknown organic substance. Calculate the molecular mass of the unknown substance.

Text Solution

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Since the two solutions are isotonic, they must have same concentrations in moles/litre.
For sucrose solution, we have concentration
`=4 g//100 cm^(3)` (given)
`=40 g L^(-1)=(40/342)"mol" L^(-1)`
(Molecular mass of sucrose `C_(12)H_(22)O_(11) =342`)
For unknown substance, suppose `m`is the molecular mass, then concentration =`3 g//100 cm^(3)` (given )
`=30 g L^(-1)=30/Mw"mol" L^(-1)`
Thus, we have `30/Mw=40/342`
`Mw=(30xx342)/40 =256.5`
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