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An aqueous solution freezes at 272.4 K w...

An aqueous solution freezes at 272.4 K while pure water freezes at 273 K. Given `K_(f)=1.86 K kg "mol"^(-1)`,`K_(b)=0.512 K kg "mol"^(-1)` and vapour pressure of water at 298 K = 23.756 mm Hg. Determine the following.
Boiling point of the solution is

A

`300.73 K`

B

`373.165 K`

C

`400 K`

D

`273.15 K`

Text Solution

Verified by Experts

The correct Answer is:
B
Boiling point of solution
`DeltaT_(f)=K_(b) xx m`
`K_(b)=0.512 K kg mol^(-1)`,`m=0.322 m` ,`DeltaT_(b)=?`
`DeltaT_(b)=0.512 xx 0.322 = 0.165^(@)`
Boiling point of solution =`373 + 0.165 =373.165 K`
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