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A solution of sucrose (molar mass =342) ...

A solution of sucrose (molar mass =342) is prepared by dissolving 68.4 g in 1000 g of water. Calculate
The vapour pressure of solution at 293 K is 0.023atm.

A

`0.0229`

B

`0.4`

C

`0.5989`

D

`0.326`

Text Solution

Verified by Experts

The correct Answer is:
A
Vapour pressure of solution can be calculated from the relation
`(P_(A)^(@)-P_(A))/P_(A)=chi_(B)=(W_(B)//Mw_(B))/(W_(A)//Mw_(A))` Here`W_(A)=1000 g`, `W_(A)=68.4 g`, `P_(A)^(@)=0.023 atm`,`Mw_(A)=18`,`Mw_(B)=342`.
Substituting the values, we get
`(0.023-P_(A))/0.023 =(68.4//342)/(1000//18)`
or
`(0.023-P_(A))/0.023 = 0.0036`
or `0.023 - 0.00008=0.02292` atm.
Vapour pressure of solution = `0.02292` atm.
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