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The electrolyte solutions show abnormal ...

The electrolyte solutions show abnormal colligative porperties.To account for this effect we define a quantity called the Van't Hoff factor given by
`i=("Actual number of particles in solution after dissociation")/("Number of formula units initially dissolved in solution")`
`i=1 ("for non-electrolytes")`
`igt1 ("for electrolytes, undergoing dissociation")`
`ilt1 ("for solutes, undergoing association")`
Answer the following questions:
`0.1 M K_(4)[Fe(CN)_(6)]` is `60%` ionized. What will be its Van't Hoff factor?

A

`1.4`

B

`3.4`

C

`2.4`

D

`4.4`

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha=(i-1)/(n-1)`,n=5 , since `K_(4)[Fe(CN)_(6)]` gives 5 ions in the solution.
`:. 0.6 =(i-1)/(5-1)`
`i=3.4`
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The Van't Hoff factor for a solute which does not dissociate or associate in solution is