Home
Class 12
CHEMISTRY
On mixing 10 mL of acetone with 40 mL of...

On mixing `10 mL` of acetone with `40 mL` of chloroform,the total volume of the solution is

A

`lt50 mL`

B

`gt50 mL`

C

`=50 mL`

D

Cannot be predicted.

Text Solution

Verified by Experts

The correct Answer is:
A

The interparticle forces in between `CHCl_(3)` and acetone increase due to H-bonding and thus `Delta_("mixing")V` becomes negative.
Promotional Banner

Similar Questions

Explore conceptually related problems

On mixing 10 mL of carbon tetrachloride with 10 mL of benzene the total volume of the solution is:

10 mL of liquid 'A' is mixed with 10 mL of liquid 'B', the volume of the resultant solution is 19.9 ml. What type of deviation expected from Raoult's law ?

10 ml of liquid A is mixed with 10ml of liquid B, the volume of the resultant solution is 19.9 ml. what type of deviation expected from Raoult's law.

Mixing of acetone with chloroform takes place with reduction in volume? What type of deviation from Raoult's law is shown in this case?

A solution contains 40 ml of ethylalcohol mixed with 100 ml of water. What is the concentration of the solution in terms of volume by volume percentage.

The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is

The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is :

100 mL of liquid A and 25 mL of liquid B are mixed to form a solution of volume 125 mL . Then the solution is

100 ml of 0.1 M solution A is mixed with 20ml of 0.2 M solution B. The final molarity of the solution is :