The factor `(DeltaT_(f)//K_(f))` represents
The factor `(DeltaT_(f)//K_(f))` represents
A
Molarity
B
Formality
C
Normality
D
Molality
Text Solution
Verified by Experts
The correct Answer is:
D
`DeltaT_(f)=K_(f) xx Molarity`
Similar Questions
Explore conceptually related problems
If DeltaT_(f) is the depression in freezing point for the electrolyte and DeltaT_(f)^(@) for the non-electrolyte of the same concentration, then Van't Hoff factor (i) is
Given that DeltaT_(f) is the depression in freezing point of the solvent in a solution of a non-volatile solute of molarity m ,the quantity underset(m rarr0)(Lt) (DeltaT_(f)//m) is equal to ……………. .
When 1.22 g C_(6)H_(5)COOH is added into two solvents, the following data of DeltaT_(b) and K_(b) are obtained: i. In 100 g CH_(3)COCH_(3) , DeltaT_(b)=0.17 , K_(b)=1.7 kg K mol^(-1) . ii. In 100 g benzene, DeltaT_(b)=0.13 and K_(b)=2.6 kg K mol^(-1) . Find out the molecular weight of C_(6)H_(5)COOH in both cases and interpret the results.
A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. A liquid possessing which of the following characteristics will be most suitable for determining the molecular mass of a compound by cryoscopic measurements?
The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"
A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. Dissolution of a non-volatile solute into a liquid leads to
A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. To aqueous solution of Nal , increasing amounts of solid Hgl_(2) is added. The vapour pressure of the solution
A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. A mixture of two immiscible liquids at a constant pressure of 1.0 atm boils at temperature
Recommended Questions
- The factor (DeltaT(f)//K(f)) represents
Text Solution
|
- Aqueous solution of barium phosphate which is 100% ionised has DeltaT(...
Text Solution
|
- NaCl is added to1 litre water to such an extent that DeltaT(f)//K(f) b...
Text Solution
|
- {:(Column-I,Column-II),("Colligative properties","Aqueous solution Ass...
Text Solution
|
- Mole fraction of a non-electrolyte in aqueous solution is 0.07. If K(f...
Text Solution
|
- Freezing point lowering expression is DeltaT(f)=K(f)m (molality) Which...
Text Solution
|
- {:(underset(("Colligative properties"))("ColumnI"),underset(("Assume m...
Text Solution
|
- Mole fraction of a non-electrolyte in aqueous solution is 0.07 . If K(...
Text Solution
|
- Aqueous solution of braium phosphate which is 100% ionised has DeltaT...
Text Solution
|